(8x+5)(x^2-4x+2)=0

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Solution for (8x+5)(x^2-4x+2)=0 equation:


Simplifying
(8x + 5)(x2 + -4x + 2) = 0

Reorder the terms:
(5 + 8x)(x2 + -4x + 2) = 0

Reorder the terms:
(5 + 8x)(2 + -4x + x2) = 0

Multiply (5 + 8x) * (2 + -4x + x2)
(5(2 + -4x + x2) + 8x * (2 + -4x + x2)) = 0
((2 * 5 + -4x * 5 + x2 * 5) + 8x * (2 + -4x + x2)) = 0
((10 + -20x + 5x2) + 8x * (2 + -4x + x2)) = 0
(10 + -20x + 5x2 + (2 * 8x + -4x * 8x + x2 * 8x)) = 0
(10 + -20x + 5x2 + (16x + -32x2 + 8x3)) = 0

Reorder the terms:
(10 + -20x + 16x + 5x2 + -32x2 + 8x3) = 0

Combine like terms: -20x + 16x = -4x
(10 + -4x + 5x2 + -32x2 + 8x3) = 0

Combine like terms: 5x2 + -32x2 = -27x2
(10 + -4x + -27x2 + 8x3) = 0

Solving
10 + -4x + -27x2 + 8x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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